首页 > SAT练习 > OG详解 > OG10 > 详情
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
  • 11
  • 12
  • 13
  • 14
  • 15
  • 16
  • 17
  • 18
  • 19
  • 20
  • 21
  • 22
  • 23
  • 24
  • 25
  • 26
  • 27
题目来源:

OG详解-OG10 数学2 Q21

正确答案:1/4
题目详解
反馈
The correct answer is 14. For an equation in slope-intercept form y = mx+b, m represents the slope of the line in the xy-plane defined by this equation. It’s given that line l is defined by 3y+12x = 5. Subtracting 12x from both sides of this equation yields 3y = -12x+5. Dividing both sides of this equation by 3 yields y =123x+53, or y = -4x+53. Thus, the slope of line l in the xy-plane is -4. Since line n is perpendicular to line l in the xy-plane, the slope of line n is the negative reciprocal of the slope of line l. The negative reciprocal of -4 is - 1(4)=14. Note that 1/4 and .25 are examples of ways to enter a correct answer.
0
题目标记:
答对了
答错了
漏选了
收藏
讨论

注:题目来源来自网络

选择你收藏的理由
发送
取消
发表评论
发送

  • 回复
  • 复制
  • 删除

取消