Choice A is correct. The y-intercept of the graph of y = f(x) in the xy-plane occurs at the point on the graph where x = 0. In other words, when x = 0, the corresponding value of f(x) is the y-coordinate of the y-intercept. Substituting 0 for x in the given equation yields f(0) = (-8)(2)0 +22, which is equivalent to f(0) = (-8)(1)+22, or f(0) = 14. Thus, when x = 0, the corresponding value of f(x) is 14. Therefore, the y-intercept of the graph of y = f(x) in the xy-plane is (0, 14).
Choice B is incorrect and may result from conceptual or calculation errors. Choice C is incorrect and may result from conceptual or calculation errors. Choice D is incorrect. This could be they-intercept for f(x) = (-8)(2)x , not f(x) = (-8)(2)x +22.