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题目来源：
OG详解-OG7 数学1 Q39
正确答案：D
题目详解
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Choice D is correct. Adding 2t to each side of the given equation yields 12n= -2w+2t. The fractions on the right side of this equation have a common
denominator of tw; therefore, the equation can be written as 12n=2wtw+2ttw , or 12n=2w−2ttw, which is equivalent to 12n=2(w−t)tw . Dividing each side of this equation by 2 yields 6n=w−ttw. Since n, t, w, and w-t are all positive quantities, taking the reciprocal of each side of the equation 6n=w−ttw yields an equivalent equation 6n=w−ttw. Multiplying each side of this equation by 6 yields n = 6tww−t .
Choice A is incorrect and may result from conceptual or calculation errors. Choice B is incorrect and may result from conceptual or calculation errors. Choice C is incorrect. This is equivalent to 1n rather than n.
denominator of tw; therefore, the equation can be written as 12n=2wtw+2ttw , or 12n=2w−2ttw, which is equivalent to 12n=2(w−t)tw . Dividing each side of this equation by 2 yields 6n=w−ttw. Since n, t, w, and w-t are all positive quantities, taking the reciprocal of each side of the equation 6n=w−ttw yields an equivalent equation 6n=w−ttw. Multiplying each side of this equation by 6 yields n = 6tww−t .
Choice A is incorrect and may result from conceptual or calculation errors. Choice B is incorrect and may result from conceptual or calculation errors. Choice C is incorrect. This is equivalent to 1n rather than n.
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