首页 > SAT练习 > OG详解 > OG2 > 详情
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
  • 11
  • 12
  • 13
  • 14
  • 15
  • 16
  • 17
  • 18
  • 19
  • 20
  • 21
  • 22
  • 23
  • 24
  • 25
  • 26
  • 27
题目来源:

OG详解-OG2 数学2 Q24

正确答案:C
题目详解
反馈
Choice C is correct. The graph of the equation  (x -h)2 + (y -k)2  = r2   in the xy-plane is a circle with center  (h, k) and a radius of length  r. The radius of a    circle is the distance from the center of the circle to any point on the circle. If a circle in the xy-plane intersects they-axis at exactly one point, then the perpendicular distance from the center of the circle to this point on they-axis must be equal to the length of the circle’s radius. It follows that the x-coordinate of the circle’s center must be equivalent to the length of the circle’s radius. In other words, if the graph of (x -h)2 + (y -k)2  = r2   is a circle that intersects the    y-axis at exactly one point, then  r = h  must be true. The equation in choice C is (x -4)2 + (y -9)2  = 16 , or (x -4)2 + (y -9)2  = 42 . This equation is in the form (x -h)2 + (y -k)2  = r2, where h = 4, k = 9, and r = 4, and represents a circle in the xy-plane with center (4,9) and radius of length  4. Substituting  4  for r  and  4  for h in the equation r = ︳h ︳yields 4 =  ︳4 ︳, or 4 = 4, which is true. Therefore, the equation in choice C represents a circle in the xy-plane that intersects they-axis at exactly one point.
Choice A is incorrect. This is the equation of a circle that does not intersect they-axis at any point. Choice B is incorrect. This is an equation of a circle that intersects the x-axis, not they-axis, at exactly one point. Choice D is incorrect. This is the equation of a circle with the center located on they-axis and thus intersects they-axis at exactly two points, not exactly one point.
0
题目标记:
答对了
答错了
漏选了
收藏
讨论

注:题目来源来自网络

选择你收藏的理由
发送
取消
发表评论
发送

  • 回复
  • 复制
  • 删除

取消